Examples of Division Problems

Make an estimate and then solve the problem. Keep track of your work in such a way that someone looking at it can understand how you solved each problem.

192 – 8 = ? Estimate: (160 – 8 = 20)

Here’s one way to figure this problem:

____

8 )192 *How many groups of 8 are in 192? 8 X ? = 192

- 80 10 *I know that there are at least 10 groups of 8 in

196.

112 * When I take those 10 groups away (80), I’m l left with 112.

80 10 *I know that there are at least 10 more groups

of 8 in 192.

32 *When I take those 10 groups away (80) I’m left with 32.

32 4 *I know that there are 4 groups of 8 in 32.

24 *When I take those 4 groups away, I’m left with no

remainders.

*Then I add all the groups together, and I get 24.

Here’s another way to figure the problem:

__

8 )192 How many groups of 8 are in 192? 8 x ? = 192

- 160 20 I know that there are two 8s in 19, so there must be

32 at least twenty 8s in 192. 20 x 8 = 160. When I take

- 32 4 160 away, I’m left with 32.

0 24 I know that there are four groups of 8 in 32. When I

take those away, I have none left.

When I add my groups, I get 20 + 4 = 24.

So, there are 24 groups of 8 in 192.

You can see that the same problem can be worked out in different ways, depending on how close a student’s first estimate is. Either way, the correct answer is obtained by continuing to estimate “how many more groups” of a number (the divisor) can be take out of the beginning big number (the dividend).